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partial quotient造句

"partial quotient"是什么意思   

例句與造句

  1. The badly approximable numbers are precisely those with bounded partial quotients.
  2. Any Liouville number must have unbounded partial quotients in its continued fraction expansion.
  3. Historically, mathematicians studied periodic continued fractions before considering the more general concept of restricted partial quotients.
  4. An irrational number is badly approximable if and only if the partial quotients of its continued fraction are bounded.
  5. Using a counting argument one can show that there exist transcendental numbers which have bounded partial quotients and hence are not Liouville numbers.
  6. It's difficult to find partial quotient in a sentence. 用partial quotient造句挺難的
  7. Serret's theorem implies that the regular continued fraction expansions of equivalent quadratic irrationalities are eventually the same, that is, their sequences of partial quotients have the same tail.
  8. It breaks down a Chunking ( also known as the partial quotients method or the hangman method ) is a less-efficient form of long division which may be easier to understand.
  9. Using the explicit continued fraction expansion of " e ", one can show that " e " is not a Liouville number ( although the partial quotients in its continued fraction expansion are unbounded ).
  10. In two dimensions, with the cone generated by \ textstyle \ { ( 1, \ alpha ), ( 1, 0 ) \ }, they are just the partial quotients of the continued fraction of \ textstyle \ alpha.
  11. Clearly any regular periodic continued fraction consists of restricted partial quotients, since none of the partial denominators can be greater than the largest of " a " 0 through " a " " k " + " m ".
  12. For example, truncating before the 4th partial quotient, we obtain the partial sum 10 / 81 = 0 . \ overline { 123456790 }, which approximates Champernowne's constant with an error of about, while truncating just before the 18th partial quotient, we get
  13. For example, truncating before the 4th partial quotient, we obtain the partial sum 10 / 81 = 0 . \ overline { 123456790 }, which approximates Champernowne's constant with an error of about, while truncating just before the 18th partial quotient, we get
  14. If " ? " is the golden ratio, then all the partial quotients " a " " n " are equal to 1, the denominators " q " " n " are the Fibonacci numbers and we recover Zeckendorf's theorem on the Fibonacci representation of positive integers as a sum of distinct non-consecutive Fibonacci numbers.

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